sub 20 babey  !

this puzzle is very interesting, you need to reject 4 qs from a silver, attach them, then also attach the leftover lead for a monomer.

the product can be made out of 3 different monomers, a line, a checkmark, and a V-shape. i started with trying out monomer assembly as i needed to do it anyways, and got down to 10 TI (later optimized all the way to 7 using the line monomer).

my first solve made it out of checkmarks for 27 TI. an arm doing grab-rotate-drop-rotate left the silver on a rejection (in a hexarm) for just enough time for another arm to move the lead into the hexarm, and a few more arms made a checkmark.

a different assembly, using the line monomer and a piston, optimized it down to 21. the piston does grab-rotate-extend-drop-retract, doing the same thing as the previous solve but better.

i got stuck on this for a bit, surely a better way exists..?

and there it was, using the technique known as "two rejection glyphs" (and a non piston arm) which allows the hexarm to grab and reject qs at top speed ! and lucky geometry made a 2 arm 6 TI handoff possible

im very pround with this solution, wishing good luck to everyone else and excited to see what magic the true TI wizards are capable of!! (less TI is definitely possible)












can you tell ti is my favourite metric